Lewis Structure of PBr3
On the Structure of Phosphorus Bromide ($PBr_3 $)
Now I would like to discuss the Lewis Structure of $PBr_3 $of phosphorus Bromide ($PBr_3 $) in detail. Phosphorus belongs to the fifteenth group of the periodic table of elements, and its outer electron number is five. Bromine belongs to the seventeenth group, and its outer electron number is seven.
In $PBr_3 $, phosphorus is the central atom. Phosphorus bonds with bromine atoms with its outer electrons. Three of the five outer electrons of phosphorus combine with one of the three bromine atoms to form three covalent bonds. In this way, there are three bonding electron pairs around phosphorus.
And phosphorus has two electrons left, and these two electrons form a pair of lone pairs of electrons. As for the bromine atom, after each bromine atom is bonded with phosphorus, in addition to the bonded electrons, there are six electrons left, and this six electrons form three pairs of lone pairs of electrons.
Looking at the Lewis structure of $PBr_3 $, it can be seen that there are three bonding electron pairs and a pair of lone pairs around the central phosphorus atom. This structure causes the molecular configuration of $PBr_3 $to be triangular conical. Because there is a repulsive force between the lone pair of electrons and the bonding electron pair, and the repulsive force between the lone pair of electrons is greater than the repulsive force between the bonding electron pairs, the bond angle of the $PBr_3 $molecule is slightly smaller than the bond angle of the regular tetrahedron 109.5 dollars ^ {\ circ} $.
From this point of view, the Lewis structure of $PBr_3 $has an important impact on the configuration and properties of its molecules. Clarifying this structure is helpful to further explore the related chemical properties and reaction mechanisms of phosphorus-containing and bromine compounds.
